Prove that 1^22^2+3^2…+(1)^{n1} n^2=(1)^{n1}\frac{ n(n+1)}{2} whenever n is a positive


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Prove that 1^22^2+3^2…+(1)^{n1} n^2=(1)^{n1}\frac{ n(n+1)}{2} whenever n is a positive

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a) Multiply the whole number 2 by the denominator 2. Whole number 2 equally 2 * 2. b) Add the answer from the previous step 4 to the numerator 1. New numerator is 4 + 1 = 5. c) Write a previous answer (new numerator 5) over the denominator 2. Two and one half is five halfs.


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1 is 1. /. 2) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the following intermediate step, it cannot further simplify the fraction result by canceling. In other words - one half divided by two is one quarter.


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$$1^2+\dotso+n^2\approx\int_0^nk^2\mathrm dk=\frac13n^3\;.$$ Share. Cite. Follow edited Aug 23, 2011 at 12:42. answered Aug 23, 2011 at 10:03. joriki joriki. 232k 14 14 gold badges 291 291 silver badges 512 512 bronze badges $\endgroup$ 1


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The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 2. 2) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the following intermediate step, it cannot further simplify the fraction result by canceling. In other words - one half divided by two is one.


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The 1-2-2 press alignment has an inherent soft spot in the middle, so players must pinch when the ball is in the middle third and must rotate to the middle when the ball is in an outer third. c. No Easy Catches or Dribbles Up the Sideline. The defense would like to trap the ball-handler up the sideline.


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